Domain Of Functions: $\frac{\sqrt{x+7}}{x-7}$ Explained

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Understanding the Domain of a Function

When we talk about the domain of a function, we're essentially asking: "What are all the possible input values (the 'x' values) that will give us a valid output (the 'f(x)' or 'y' value)?" Think of it like a recipe; not all ingredients will work together to create a delicious dish. Similarly, not all numbers can be plugged into a function without causing problems like dividing by zero or taking the square root of a negative number. In this article, we're going to break down how to find the domain of a specific function, f(x)=x+7xβˆ’7f(x)=\frac{\sqrt{x+7}}{x-7}, and express it using interval notation, which is a common and precise way mathematicians like to show these ranges of numbers. We'll explore the two main conditions that restrict the domain in this particular function: the presence of a square root and a denominator. Understanding these restrictions is key to mastering function domains, a fundamental concept in algebra and calculus. We'll go step-by-step, ensuring that by the end, you'll feel confident in tackling similar problems yourself. Remember, the domain is all about identifying the 'safe zones' for your input values where the function behaves as expected and produces a real number output. So, let's dive in and demystify the process of finding the domain for f(x)=x+7xβˆ’7f(x)=\frac{\sqrt{x+7}}{x-7}!

Identifying Restrictions in f(x)=x+7xβˆ’7f(x)=\frac{\sqrt{x+7}}{x-7}

The function f(x)=x+7xβˆ’7f(x)=\frac{\sqrt{x+7}}{x-7} presents two primary challenges when determining its domain: the square root in the numerator and the denominator. Each of these components imposes its own set of rules that our input values, 'x', must adhere to. Let's tackle the square root first. You can never take the square root of a negative number and get a real number result. This is a fundamental rule in mathematics. Therefore, the expression inside the square root, which is (x+7)(x+7) in our function, must be greater than or equal to zero. This inequality, x+7β‰₯0x+7 \ge 0, is our first major restriction. Solving this simple inequality by subtracting 7 from both sides gives us xβ‰₯βˆ’7x \ge -7. This means that any 'x' value less than -7 will result in trying to find the square root of a negative number, which is undefined in the realm of real numbers. So, all our valid 'x' values must start from -7 and go upwards.

Now, let's turn our attention to the second restriction: the denominator. In any fraction, the denominator can never be equal to zero. If the denominator is zero, we encounter a 'division by zero' error, which is mathematically undefined. In our function, the denominator is (xβˆ’7)(x-7). So, we must ensure that xβˆ’7β‰ 0x-7 \ne 0. To find the value of 'x' that causes this problem, we simply solve the equation xβˆ’7=0x-7 = 0. Adding 7 to both sides reveals that xβ‰ 7x \ne 7. This means that the number 7 is explicitly excluded from our domain. Even though x=7x=7 would not cause an issue with the square root (since 7+7=147+7=14, which is positive), it makes the entire fraction undefined. Therefore, we have two critical conditions: xβ‰₯βˆ’7x \ge -7 and xβ‰ 7x \ne 7. Our goal is to combine these conditions to define the complete set of valid inputs for our function.

Combining Restrictions and Interval Notation

We've identified two crucial restrictions for the domain of the function f(x)=x+7xβˆ’7f(x)=\frac{\sqrt{x+7}}{x-7}: first, the expression under the square root must be non-negative (xβ‰₯βˆ’7x \ge -7), and second, the denominator cannot be zero (xβ‰ 7x \ne 7). Now, we need to combine these conditions to define the complete set of allowed input values. The condition xβ‰₯βˆ’7x \ge -7 tells us that our domain starts at -7 and extends infinitely in the positive direction. In interval notation, this part of the domain is represented as [βˆ’7,∞)[-7, \infty). The square bracket at -7 indicates that -7 itself is included in the domain, while the parenthesis at infinity signifies that infinity is not a number we can reach, so it's always represented with a parenthesis. However, we also have the restriction that xβ‰ 7x \ne 7. This means that even though 7 is included in the interval [βˆ’7,∞)[-7, \infty) (since 7β‰₯βˆ’77 \ge -7), we must exclude it from our domain.

To exclude a single point from an interval, we use the union symbol (βˆͺ\cup) to combine separate intervals. We need to consider the part of the interval [βˆ’7,∞)[-7, \infty) that is less than 7, and the part that is greater than 7. The values of 'x' that satisfy both xβ‰₯βˆ’7x \ge -7 and x<7x < 7 form the interval [βˆ’7,7)[-7, 7). Here, -7 is included (square bracket), but 7 is excluded (parenthesis) because xβ‰ 7x \ne 7. The values of 'x' that satisfy both x>7x > 7 (since we must exclude 7 and continue towards positive infinity, and xless7x less 7 from the previous part) form the interval (7,∞)(7, \infty). Here, 7 is excluded (parenthesis) and infinity is also represented with a parenthesis. Combining these two intervals using the union symbol gives us the final domain of the function in interval notation: [βˆ’7,7)βˆͺ(7,∞)[-7, 7) \cup (7, \infty). This notation precisely states that all real numbers from -7 up to, but not including, 7, AND all real numbers greater than 7, are valid inputs for our function f(x)=x+7xβˆ’7f(x)=\frac{\sqrt{x+7}}{x-7}. It's a concise way to represent a set of numbers with specific inclusions and exclusions. Mastering this process ensures you can accurately define the boundaries of any function you encounter.

Conclusion: Mastering Function Domains

Finding the domain of a function is a critical skill in mathematics, essential for understanding a function's behavior and its limitations. For the function f(x)=x+7xβˆ’7f(x)=\frac{\sqrt{x+7}}{x-7}, we successfully identified two key restrictions: the expression under the square root must be non-negative (xβ‰₯βˆ’7x \ge -7), and the denominator cannot be zero (xβ‰ 7x \ne 7). By carefully combining these conditions, we arrived at the domain expressed in interval notation as [βˆ’7,7)βˆͺ(7,∞)[-7, 7) \cup (7, \infty). This means that any real number greater than or equal to -7, except for 7 itself, is a valid input for this function. This process highlights the importance of scrutinizing every part of a function – denominators, square roots, logarithms, and other potential sources of undefined results – to accurately determine where a function is well-defined.

Practice is key to solidifying your understanding of domains. As you encounter more complex functions, you'll develop a systematic approach to identifying and resolving restrictions. Remember to always consider the specific mathematical operations involved and their inherent constraints. For further exploration into the broader concepts of functions and their properties, you might find the resources at Khan Academy to be incredibly helpful. Their comprehensive explanations and practice exercises can deepen your understanding of these foundational mathematical concepts. Keep practicing, and you'll become adept at navigating the world of function domains!